-x^2+8x-52=0

Solution for -x^2+8x-52=0 equation:

Simplifying
-1x2 + 8x + -52 = 0

Reorder the terms:
-52 + 8x + -1x2 = 0

Solving
-52 + 8x + -1x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
52 + -8x + x2 = 0

Move the constant term to the right:

Add '-52' to each side of the equation.
52 + -8x + -52 + x2 = 0 + -52

Reorder the terms:
52 + -52 + -8x + x2 = 0 + -52

Combine like terms: 52 + -52 = 0
0 + -8x + x2 = 0 + -52
-8x + x2 = 0 + -52

Combine like terms: 0 + -52 = -52
-8x + x2 = -52

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -52 + 16

Reorder the terms:
16 + -8x + x2 = -52 + 16

Combine like terms: -52 + 16 = -36
16 + -8x + x2 = -36

Factor a perfect square on the left side:
(x + -4)(x + -4) = -36

Can't calculate square root of the right side.

The solution to this equation could not be determined.